Question Number 103421 by aurpeyz last updated on 15/Jul/20

Answered by Worm_Tail last updated on 15/Jul/20

v_y ^2 =(usinθ)^2 −2gs_y ⇒3.7^2 =(usinθ)^2 −(2×10×7.5)  13.69+150=(usinθ)^2 ⇒(usinθ)^2 =163.69  h_(max) =(((usinθ)^2 )/(2g))=((163.69)/(20))=8.1845m  T=((2(usinθ))/g)=((2×(√(163.69)))/(10))=2.5588s  R=v_x T=10.4×2.5588=26.61m

Commented byaurpeyz last updated on 15/Jul/20

thanks sir