Question Number 10355 by Tawakalitu ayo mi last updated on 05/Feb/17

What is the escape velocity from the surface  of a planet with two third of the earth′s  gravity but the same radius.

Commented byTawakalitu ayo mi last updated on 05/Feb/17

i will reduce it sir.

Answered by mrW1 last updated on 05/Feb/17

Escape velocity v=(√((2Gm)/R))  with G=universal gravitational constant             m=Mass of planet             R=Radius of planet    (v_x /v_(earth) )=(√(m_x /m_(earth) ))=(√(2/3))=0.816  Escape velocity of planet X is  v_x =0.816v_(earth) =0.816×11.2=9.1 km/s

Commented byTawakalitu ayo mi last updated on 05/Feb/17

God bless you sir.