Question Number 10364 by Joel575 last updated on 05/Feb/17

1+2+3+4+5+6+7+8+9+10+11 = x^y   The sum of all possible solutions of x and y is ...

Answered by mrW1 last updated on 05/Feb/17

1+2+3+4+5+6+7+8+9+10+11=((11×12)/2)=66  x^y =66  yln x=ln 66  y=((ln 66)/(ln x))  x∈R,x>0, x≠1  ⇒if x and y can be real numbers,  there are infinite solutions.    if x and y are integers, there is only  one solution:  x=66, y=1  since 66=2×3×11

Commented byJoel575 last updated on 06/Feb/17

thank you sirr