Question Number 103685 by bemath last updated on 16/Jul/20

Answered by bobhans last updated on 16/Jul/20

x−(√((2−x)(3−x))) = (√(4−x)){(√(3−x))+(√(2−x))}  2x^2 −5x+6−2x(√((2−x)(3−x))) =  (4−x)(5−2x)+2(√((3−x)(2−x)))  4x−7 =  x(√((2−x)(3−x)))+(4−x)(√((2−x)(3−x)))  4x−7 = 4(√((2−x)(3−x)))  (4x−7)^2  = 16(6−5x+x^2 )  −56x+49 = 96−80x   24x = 47 ⇒ x = ((47)/(24)) ★