Question Number 103685 by bemath last updated on 16/Jul/20

Answered by bobhans last updated on 16/Jul/20

x−(√((2−x)(3−x))) = (√(4−x)){(√(3−x))+(√(2−x))} 2x^2 −5x+6−2x(√((2−x)(3−x))) = (4−x)(5−2x)+2(√((3−x)(2−x))) 4x−7 = x(√((2−x)(3−x)))+(4−x)(√((2−x)(3−x))) 4x−7 = 4(√((2−x)(3−x))) (4x−7)^2 = 16(6−5x+x^2 ) −56x+49 = 96−80x 24x = 47 ⇒ x = ((47)/(24)) ★