Question Number 10391 by 314159 last updated on 06/Feb/17

Find the equation of the straight  line through (2,3)   (i)parallel to  (ii)perpendicular to 2x−3y+6=0

Answered by mrW1 last updated on 06/Feb/17

2x−3y+6=0  ⇒y=(2/3)x+2    (i)  y−3=(2/3)(x−2)  2x−3y+5=0    (ii)  y−3=−(3/2)(x−2)  3x+2y−12=0