Question Number 10391 by 314159 last updated on 06/Feb/17

Find the equation of the straight line through (2,3) (i)parallel to (ii)perpendicular to 2x−3y+6=0

Answered by mrW1 last updated on 06/Feb/17

2x−3y+6=0 ⇒y=(2/3)x+2 (i) y−3=(2/3)(x−2) 2x−3y+5=0 (ii) y−3=−(3/2)(x−2) 3x+2y−12=0