Question Number 10392 by ketto last updated on 06/Feb/17

find the direction cosines and its angles on 2i − 3j

Answered by mrW1 last updated on 07/Feb/17

cos α=(2/(√(2^2 +(−3)^2 )))=(2/(√(13))) cos β=((−3)/(√(2^2 +(−3)^2 )))=−(3/(√(13))) α=56.3° β=146.3°