Question Number 104207 by PengagumRahasiamu last updated on 20/Jul/20

Answered by bemath last updated on 20/Jul/20

x^2 −x+1 = 0  x= ((1 ± i(√3))/2) = (1/2)± ((i(√3))/2)  have no real roots. Sum of  real root is nothing

Answered by OlafThorendsen last updated on 20/Jul/20

if a root is z = α+iβ  the second root is z^_  = α−iβ  The sum of its real root is  z+z^_  = 2α  In fact the sum is −(b/a) = −((−1)/1)  So z+z^_  = 1  but the question is not clear  you should answer ♮nothingε