Question Number 104301 by aurpeyz last updated on 20/Jul/20

a girl weighs 569.37N on the earth surfsce (a) what would she weigh at a height above the earth surface of one earth radius? what would her mass be?

Commented bymr W last updated on 20/Jul/20

what if you don′t write the whole  post in a single line? thanks!

Commented byaurpeyz last updated on 01/Aug/20

I will do that better another time Sir . thanks

Answered by OlafThorendsen last updated on 20/Jul/20

P^→  = ((mMG)/((R+z)^2 ))u^→  = mg^→ (z)  P_0 ^→  = ((mMG)/R^2 )u^→  = mg_0 ^→   (P/P_0 ) = (R^2 /((R+z)^2 )) = (1/((1+(z/R))^2 ))  If z = R  (P/P_0 ) =  (1/((1+1)^2 )) = (1/4)  P = (P_0 /4) = ((569,37)/4) = 142,34 N

Commented byaurpeyz last updated on 01/Aug/20

whatwill her mass be?

Answered by Dwaipayan Shikari last updated on 20/Jul/20

(g/g^′ )=(((R+H)^2 )/R^2 )  ((mg)/(mg^′ ))=(((2R)^2 )/R^2 )⇒mg^′ =((mg)/4)=((569.37)/4)=142.3425 N

Commented byaurpeyz last updated on 01/Aug/20

what will her mass be?

Commented byaurpeyz last updated on 01/Aug/20

pls help