Question Number 104359 by bemath last updated on 21/Jul/20

solve this using Riemann  sum f(x)=2x ; [0,4] for n=4

Answered by Ar Brandon last updated on 21/Jul/20

∫_0 ^4 2xdx=lim_(n→∞) ((4−0)/n)Σ_(k=1) ^n 2(0+((4k)/n))=lim_(n→∞) (4/n)Σ_(k=1) ^n ((8k)/n)                  =lim_(n→∞) ((32)/n^2 )∙((n(n+1))/2)=lim_(n→∞) 16(1+(1/n))=16