Question Number 104369 by quvonchbek3737 last updated on 21/Jul/20

Answered by mr W last updated on 21/Jul/20

6((3)^(1/x) )^2 −13((3)^(1/x) )((2)^(1/x) )+6((2)^(1/3) )^2 =0 6(((3/2))^(1/x) )^2 −13(((3/2))^(1/x) )+6=0 ((3/2))^(1/x) =((3/2))^x =((13±(√(13^2 −4×6×6)))/(2×6))=(3/2),(2/3) ⇒x=±1