Question Number 10451 by ketto last updated on 09/Feb/17

Answered by amir last updated on 10/Feb/17

Σf_x =10cos45−10cos45+0=0  Σf_y =2×10sin45−9=10(√2)−9#5.41  R=(√((Σf_x )^2 +(Σf_y )^2 ))=(√(0^2 +5.4^2 1))=5.41■

Answered by ridwan balatif last updated on 10/Feb/17