Question Number 1047 by 112358 last updated on 23/May/15

Simplify the following  expression using the laws of   Boolean algebra:  (x∧∽y)∨(∽y∧∽z)∨(∽x∧∽z) .

Commented byprakash jain last updated on 24/May/15

∽x∧∽z=∽(x∨z)  ∽y∧∽z=∽(y∨z)  (∽(y∨z))∨(∽(x∨z))=∽((y∨z)∧(x∨z))  =∽((y∧x)∨z)