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Question Number 105842 by aurpeyz last updated on 01/Aug/20

A wheel revolving at 6rev/s has an angular   acceleration of 4rad/s^2 . find the number of   turns the wheel must take to reach 26rev/s  and the time required.

$$\mathrm{A}\:\mathrm{wheel}\:\mathrm{revolving}\:\mathrm{at}\:\mathrm{6rev}/\mathrm{s}\:\mathrm{has}\:\mathrm{an}\:\mathrm{angular}\: \\ $$$$\mathrm{acceleration}\:\mathrm{of}\:\mathrm{4rad}/\mathrm{s}^{\mathrm{2}} .\:\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\: \\ $$$$\mathrm{turns}\:\mathrm{the}\:\mathrm{wheel}\:\mathrm{must}\:\mathrm{take}\:\mathrm{to}\:\mathrm{reach}\:\mathrm{26rev}/\mathrm{s} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{time}\:\mathrm{required}. \\ $$

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