Question Number 11151 by suci last updated on 14/Mar/17 | ||
$${f}\left({x}\right)=\mathrm{2}^{\frac{\mathrm{1}−{x}}{\mathrm{2}+{x}^{\mathrm{2}} }} \\ $$$${f}'\left({x}\right)=...??? \\ $$ | ||
Answered by ajfour last updated on 14/Mar/17 | ||
$$=\:\mathrm{2}^{\frac{\mathrm{1}−{x}}{\mathrm{2}+{x}^{\mathrm{2}} }} \left(\mathrm{ln}\:\mathrm{2}\right)\left[\frac{{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{2}}{\left({x}^{\mathrm{2}} +\mathrm{2}\right)^{\mathrm{2}} }\right] \\ $$ | ||