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Question Number 11352 by tawa last updated on 21/Mar/17

if,  A = x^2  sin yi + z^2  cos yj − xy^2 k,  find,  dA

$$\mathrm{if},\:\:\mathrm{A}\:=\:\mathrm{x}^{\mathrm{2}} \:\mathrm{sin}\:\mathrm{yi}\:+\:\mathrm{z}^{\mathrm{2}} \:\mathrm{cos}\:\mathrm{yj}\:−\:\mathrm{xy}^{\mathrm{2}} \mathrm{k},\:\:\mathrm{find},\:\:\mathrm{dA}\:\: \\ $$

Answered by sm3l2996 last updated on 22/Mar/17

dA=(2xsin(y)i−y^2 k)dx+(x^2 cos(y)i−z^2 sin(y)j−2xyk)dy+2zcos(y)dzj

$$\mathrm{dA}=\left(\mathrm{2xsin}\left(\mathrm{y}\right)\mathrm{i}−\mathrm{y}^{\mathrm{2}} \mathrm{k}\right)\mathrm{dx}+\left(\mathrm{x}^{\mathrm{2}} \mathrm{cos}\left(\mathrm{y}\right)\mathrm{i}−\mathrm{z}^{\mathrm{2}} \mathrm{sin}\left(\mathrm{y}\right)\mathrm{j}−\mathrm{2xyk}\right)\mathrm{dy}+\mathrm{2zcos}\left(\mathrm{y}\right)\mathrm{dzj} \\ $$

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