Question Number 113862 by Aina Samuel Temidayo last updated on 15/Sep/20

Answered by 1549442205PVT last updated on 16/Sep/20

From the hypotesis we have  ((logx)/(b−c))=((logy)/(c−a))=((logz)/(a−b))=k.Hence,we get   { ((logx=k(b−c))),((logy=k(c−a))),((logz=k(a−b))) :}  Adding up three equalities we obtain  logx+logy+logz=k(b−c+c−a+a−b)  ⇒log(xyz)=k.0=0⇒xyz=1  Therefore,we choose a)