Question Number 113885 by Aina Samuel Temidayo last updated on 16/Sep/20

Answered by MJS_new last updated on 16/Sep/20

x=((ln bc)/(ln a))     y=((ln ac)/(ln b))     z=((ln ab)/(ln c))  ln a =o; ln b =p ; ln c =q  xyz=(o/p)+(o/q)+(p/o)+(p/q)+(q/o)+(q/p)+2=x+y+z+2