Question Number 114071 by bobhans last updated on 17/Sep/20

Find the solution set (√(x^2 −4x−5)) ≥ x

Commented byprakash jain last updated on 17/Sep/20

Commented bybemath last updated on 17/Sep/20

how do you made this graph sir

Commented byprakash jain last updated on 17/Sep/20

From this app only, i was just checking steps: a. insert drawing b. insert equation and pasted equation 1. c. from BUILD menu select plot d. repeated procedure for other equation. see Q113542.

Commented bybemath last updated on 17/Sep/20

thank you sir

Answered by bemath last updated on 17/Sep/20

(1) x^2 −4x−5 ≥ 0 (x−5)(x+1) ≥ 0 x ≤ −1 ∪ x≥ 5 (2) check for x = −1 (√((−1)^2 −4(−1)−5)) = (√(5−5)) = 0 ≥−1 (true) check for x=5 (√(25−20−5)) = 0 ≥ 5 (false) then solution is x ≤−1

Commented bybemath last updated on 17/Sep/20

Commented bybobhans last updated on 17/Sep/20

santuyy