Question Number 114071 by bobhans last updated on 17/Sep/20

Find the solution set   (√(x^2 −4x−5)) ≥ x

Commented byprakash jain last updated on 17/Sep/20

Commented bybemath last updated on 17/Sep/20

how do you made this graph sir

Commented byprakash jain last updated on 17/Sep/20

From this app only, i was just  checking  steps:  a. insert drawing  b. insert equation and pasted equation 1.  c. from BUILD menu select plot  d. repeated procedure for other equation.  see Q113542.

Commented bybemath last updated on 17/Sep/20

thank you sir

Answered by bemath last updated on 17/Sep/20

(1) x^2 −4x−5 ≥ 0        (x−5)(x+1) ≥ 0        x ≤ −1 ∪ x≥ 5  (2) check for x = −1    (√((−1)^2 −4(−1)−5)) = (√(5−5)) = 0 ≥−1 (true)  check for x=5   (√(25−20−5)) = 0 ≥ 5 (false)  then solution is x ≤−1

Commented bybemath last updated on 17/Sep/20

Commented bybobhans last updated on 17/Sep/20

santuyy