Question Number 11408 by anisa last updated on 24/Mar/17

Answered by sm3l2996 last updated on 24/Mar/17

=((sin(((4π)/3))+cos(((4π)/3)))/(tg(((4π)/3))))=((((−(√3))/2)−(1/2))/(√3)) =−(((√3)+1)/(2(√3)))