Question Number 114114 by aurpeyz last updated on 17/Sep/20

  A 50g golf ball is struck with a club moving  with a velocity of 22m/s after it moves 4cm and  ball accelerates with a velocity of 44m/s.  estimate the average force exerted by the club  on the ball.

Commented byaurpeyz last updated on 17/Sep/20

pls help

Answered by Ar Brandon last updated on 17/Sep/20

m_b =0.05Kg, u_b =0m/s, v_b =44m/s, m_c =?, u_c =22m/s  v_c =0m/s. Momentum is conserved  ⇒m_b u_b +m_c u_c =m_b v_b +m_c v_c ⇒22m_c =44×0.05  ⇒m_c =0.1Kg  For club;  v=0m/s, a=?, u=22m/s, s=4cm=0.04m  Using v^2 =u^2 +2as, 0=22^2 +2a×0.04⇒a=−6050m/s^2   ⇒F=ma=0.1×6050=605 N