Question Number 114295 by mathdave last updated on 18/Sep/20
Answered by mr W last updated on 19/Sep/20
![say the number is [abcde] let A=a+c+e B=b+d A+B=41 (as given) A−B=0 or ±11, ±22, ... ⇒A=20, B=21 (impossible, since B<2×9=18) ⇒A=26, B=15 ⇒A=37, B=4 (impossible, since A<3×9=27) so we have only one possibility: A=26, B=15 ⇒A=9+9+8 ⇒B=9+6 ⇒smallest number is 86999 ⇒largest number is 99968](Q114341.png)