Question Number 114375 by A8;15: last updated on 18/Sep/20

Commented byA8;15: last updated on 18/Sep/20

please help

Commented byMJS_new last updated on 18/Sep/20

x=9 y=4 z=1  sorry I saw this at first glance...

Commented byA8;15: last updated on 19/Sep/20

thanks sir

Answered by bemath last updated on 19/Sep/20

u+v^2 +w^2 =8→u=8−(v^2 +w^2 )  u^2 +v+w^2 =12→u^2 =12−v−w^2   u^2 +v^2 +w=14→u^2 =14−v^2 −w  ⇔ 12−v−w^2 =14−v^2 −w  ⇔v^2 −v =2+w^2 −w  ⇔v^2 −w^2 −(v−w)=2  ⇔ (v−w){(v+w)−1}=2  v−w = (2/(v+w−1))

Commented byMJS_new last updated on 19/Sep/20

yes but try to solve it to the end. it′s getting  complicated  if we have nice numbers as here it′s possible  to find them but trt  (√x)+y+z=7  x+(√y)+z=11  x+y+(√z)=13

Commented byA8;15: last updated on 19/Sep/20

thank you sir !