Question Number 114379 by A8;15: last updated on 18/Sep/20

Commented byA8;15: last updated on 18/Sep/20

please help

Answered by mr W last updated on 19/Sep/20

Commented bymr W last updated on 19/Sep/20

AC=x  AE=HF=(√((4+1)^2 −(4−1)^2 ))=4  CE=x−4=CG  BG=BC−CG=(√(x^2 +8^2 ))−x+4  BF^2 =7^2 +4^2 =65  BF^2 =1^2 +BG^2 =1+((√(x^2 +8^2 ))−x+4)^2   1+((√(x^2 +8^2 ))−x+4)^2 =65  (√(x^2 +8^2 ))−x+4=8  (√(x^2 +8^2 ))=4+x  ⇒x=6

Commented byA8;15: last updated on 19/Sep/20

thank you sir!