Question Number 11459 by @ANTARES_VY last updated on 26/Mar/17

If  ((4x^2 −4xy+3y^2 )/(2y^2 +2xy−5x^2 ))=1  if  the  ((x+y)/(x−y))  what  is  th  value?

Answered by ajfour last updated on 26/Mar/17

−2

Commented byajfour last updated on 26/Mar/17

((4x^2 −4xy+3y^2 )/(2y^2 +2xy−5x^2 ))  ; dividing N^r  and D^r  by  y^2  yields  =((4((x/y))^2 −4((x/y))+3)/(2+2((x/y))−5((x/y))^2 )) =1  let m=(x/y)  ((4m^2 −4m+3)/(2+2m−5m^2 )) =1  ⇒   4m^2 −4m+3=2+2m−5m^2   9m^2 −6m+1=0  (3m−1)^2 =1   ⇒  m=(x/y)=(1/3)  Now, ((x+y)/(x−y)) = ((1+3)/(1−3)) = −2

Answered by ridwan balatif last updated on 26/Mar/17

4x^2 −4xy+3y^2 =2y^2 +2xy−5x^2   9x^2 −6xy=−y^2   9x^2 −6xy+y^2 =0  (3x−y)=0  3x=y  ((x+y)/(x−y))=((x+3x)/(x−3x))=−2

Commented by@ANTARES_VY last updated on 26/Mar/17

THENKS

Commented by@ANTARES_VY last updated on 26/Mar/17

THENKS