Question Number 114615 by I want to learn more last updated on 19/Sep/20

Answered by Olaf last updated on 19/Sep/20

t is the scheduled time  x = v_1 t_1  = 45(t+(1/(20))) (1)  x = v_2 t_2  = 60(t−(3/(20))) (2)  ((1/(20)) h = 3 min and (3/(20)) h = 9 min)  (1)−(3/4)×(2) :  x−(3/4)x = 45(t+(1/(20)))−(3/4)×60(t−(3/(20)))  (1/4)x = ((45)/(20))+((45×3)/(20)) = 9 km  ⇒ x = 4×9 = 36 km  with (1) : t+(1/(20)) = (x/(45)) = ((36)/(45)) = (4/5)  t = (4/5)−(1/(20)) = (3/4) h = 45 min

Commented byI want to learn more last updated on 20/Sep/20

Thanks sir, i appreciate