Question Number 114863 by mathdave last updated on 21/Sep/20

find four consecutive multiples of 5 such that twice the sum of the two greatest integer exceed five times the least by 5

Answered by PRITHWISH SEN 2 last updated on 21/Sep/20

let the integrs are (5m−10),(5m−5),5m,(5m+5) by the problem 2{5m+(5m+5)}=5(5m−10)+5 ⇒m= 11 ∴ the numbers are 45,50,55,60