Question Number 114863 by mathdave last updated on 21/Sep/20

find four consecutive multiples of 5  such that twice the sum of the two  greatest integer exceed five times the  least by 5

Answered by PRITHWISH SEN 2 last updated on 21/Sep/20

let the integrs are           (5m−10),(5m−5),5m,(5m+5)  by the problem     2{5m+(5m+5)}=5(5m−10)+5           ⇒m= 11       ∴ the numbers are                             45,50,55,60