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Question Number 119452 by peter frank last updated on 24/Oct/20
Commented by TANMAY PANACEA last updated on 24/Oct/20
$${feeding}\:{now}\:{become}\:{slow}...{no}\:{body}\:{share}\:{olympiad}\:{question} \\ $$
Answered by Olaf last updated on 24/Oct/20
$$\mathrm{S}_{\mathrm{b}} −\mathrm{Z}_{\mathrm{n}} \:=\:\frac{\Delta\mathrm{V}}{\Delta\mathrm{T}} \\ $$$$\Delta\mathrm{V}\:=\:\left(\mathrm{S}_{\mathrm{b}} −\mathrm{Z}_{\mathrm{n}} \right)\left(\theta_{\mathrm{2}} −\theta_{\mathrm{1}} \right) \\ $$$$\Delta\mathrm{V}\:=\:\left(\mathrm{43}.\mathrm{9}×\mathrm{10}^{−\mathrm{6}} −\mathrm{3}.\mathrm{4}×\mathrm{10}^{−\mathrm{6}} \right)\left(\mathrm{110}−\mathrm{10}\right) \\ $$$$\Delta\mathrm{V}\:=\:\mathrm{4050}×\mathrm{10}^{−\mathrm{6}} \:\mathrm{V}\:=\:\mathrm{4050}\mu\mathrm{V} \\ $$$$−\boldsymbol{\mathrm{thermoelectricity}} \\ $$$$−\boldsymbol{\mathrm{Seebeck}}\:\boldsymbol{\mathrm{effect}} \\ $$
Commented by Dwaipayan Shikari last updated on 24/Oct/20
$${Olaf}\:{sir}\:!\:{are}\:{you}\:{a}\:{physicist}? \\ $$
Commented by peter frank last updated on 24/Oct/20
$$\mathrm{thank}\:\mathrm{you} \\ $$