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Question Number 125437 by SOMEDAVONG last updated on 11/Dec/20

show that (E):m(x−1)^(2017) (x+2)^(2018) +2x+3=0 have root ∀m∈R.

$$\mathrm{show}\:\mathrm{that}\:\left(\mathrm{E}\right):\mathrm{m}\left(\mathrm{x}−\mathrm{1}\right)^{\mathrm{2017}} \left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{2018}} +\mathrm{2x}+\mathrm{3}=\mathrm{0}\:\mathrm{have}\:\mathrm{root}\:\forall\mathrm{m}\in\mathbb{R}. \\ $$

Commented by Snail last updated on 11/Dec/20

I have a doubt what type of root it has when   m∈R....please say the condition properly

$${I}\:{have}\:{a}\:{doubt}\:{what}\:{type}\:{of}\:{root}\:{it}\:{has}\:{when}\: \\ $$$${m}\in\mathbb{R}....{please}\:{say}\:{the}\:{condition}\:{properly} \\ $$

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