Question Number 132064 by I want to learn more last updated on 10/Feb/21
Commented by mr W last updated on 11/Feb/21
$$\left({m}_{\mathrm{1}} +{m}_{\mathrm{2}} \right){a}=\left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right){g} \\ $$$${a}=\frac{{m}_{\mathrm{1}} −{m}_{\mathrm{2}} }{{m}_{\mathrm{1}} +{m}_{\mathrm{2}} }{g} \\ $$$${v}=\sqrt{\mathrm{2}{ah}}=\sqrt{\frac{\mathrm{2}{gh}\left({m}_{\mathrm{1}} −{m}_{\mathrm{2}} \right)}{{m}_{\mathrm{1}} +{m}_{\mathrm{2}} }} \\ $$
Commented by I want to learn more last updated on 11/Feb/21
$$\mathrm{Thanks}\:\mathrm{sir},\:\:\mathrm{i}\:\mathrm{really}\:\mathrm{areciate}. \\ $$