Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 14181 by tawa tawa last updated on 29/May/17

∫ sec^6 (x)  dx

$$\int\:\mathrm{sec}^{\mathrm{6}} \left(\mathrm{x}\right)\:\:\mathrm{dx}\:\: \\ $$

Answered by ajfour last updated on 29/May/17

let tan x=t  ⇒sec^2 xdx=dt, and we know  1+tan^2 x=sec^2 x  ∫(sec^4 x)sec^2 xdx =∫(1+t^2 )^2 dt       =∫(1+2t^2 +t^4 )dx       =t+(2/3)t^3 +(t^5 /5)+C .     (replace tan x for t ) .

$${let}\:\mathrm{tan}\:{x}={t} \\ $$$$\Rightarrow\mathrm{sec}\:^{\mathrm{2}} {xdx}={dt},\:{and}\:{we}\:{know} \\ $$$$\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} {x}=\mathrm{sec}\:^{\mathrm{2}} {x} \\ $$$$\int\left(\mathrm{sec}\:^{\mathrm{4}} {x}\right)\mathrm{sec}\:^{\mathrm{2}} {xdx}\:=\int\left(\mathrm{1}+{t}^{\mathrm{2}} \right)^{\mathrm{2}} {dt} \\ $$$$\:\:\:\:\:=\int\left(\mathrm{1}+\mathrm{2}{t}^{\mathrm{2}} +{t}^{\mathrm{4}} \right){dx} \\ $$$$\:\:\:\:\:={t}+\frac{\mathrm{2}}{\mathrm{3}}{t}^{\mathrm{3}} +\frac{{t}^{\mathrm{5}} }{\mathrm{5}}+{C}\:. \\ $$$$\:\:\:\left({replace}\:\mathrm{tan}\:{x}\:{for}\:\boldsymbol{{t}}\:\right)\:. \\ $$

Commented by tawa tawa last updated on 29/May/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com