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Question Number 146756 by Bens last updated on 15/Jul/21

    ∫_( 0) ^( 1)  t^2  + 1 dt

$$ \\ $$$$ \\ $$$$\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:{t}^{\mathrm{2}} \:+\:\mathrm{1}\:{dt} \\ $$

Answered by tabata last updated on 15/Jul/21

((t^3 /3)+t)^3 _0 =(((27)/3)+3)=9+3=12

$$\left(\frac{{t}^{\mathrm{3}} }{\mathrm{3}}+{t}\underset{\mathrm{0}} {\right)}^{\mathrm{3}} =\left(\frac{\mathrm{27}}{\mathrm{3}}+\mathrm{3}\right)=\mathrm{9}+\mathrm{3}=\mathrm{12} \\ $$

Answered by puissant last updated on 15/Jul/21

=[(t^3 /3)+t]_0 ^1 = (4/3)..

$$=\left[\frac{\mathrm{t}^{\mathrm{3}} }{\mathrm{3}}+\mathrm{t}\right]_{\mathrm{0}} ^{\mathrm{1}} =\:\frac{\mathrm{4}}{\mathrm{3}}.. \\ $$

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