Question Number 148276 by 0731619 last updated on 26/Jul/21

Answered by mathmax by abdo last updated on 26/Jul/21

y(n)=e^(((n^2 +n)/(n^3 −4n^2 ))log2) ⇒(dy/dn)=(d/dn)(log2×((n^2 +n)/(n^3 −4n^2 )))y(n) =log2(((n+1)/(n^2 −4n)))^((1)) y(n) =log2(((n^2 −4n−(n+1)(2n−4))/((n^2 −4n)^2 )))y(n) =log2×((n^2 −4n−(2n^2 −2n−4))/((n^2 −4n)^2 ))y(n) =log2×((−n^2 −2n+4)/((n^2 −4n)^2 ))y(n) ⇒ (dy/dn)=−log(2)×((n^2 +2n−4)/((n^2 −4n)^2 ))y(n)