Question Number 148285 by Khalmohmmad last updated on 26/Jul/21

∫_1 ^∞ (1/(x^2 lnx))dx=?

Commented byahmedNasser last updated on 26/Jul/21

let u = lnx ∴ du = (1/x) dx x = e^u ∫_0 ^( ∞) (1/(e^(2u) ∙u)) ∙e^u du =∫_0 ^( ∞) u^(−1) e^(−u) du =Γ(0) = ∞

Answered by puissant last updated on 26/Jul/21

diverge..