Question Number 148321 by mathdanisur last updated on 27/Jul/21

Answered by dumitrel last updated on 27/Jul/21

p(x)=x^(2021) −x−1,x>0 p(a)=0;p(x) ↗ for x∈(a,∞);a>1 if b≥a⇒f(b)≥f(a)=0⇒b^(2021) ≥b+1⇒ b^(4042) ≥b^2 +2b+1⇒3a+b≥b^2 +2b+1⇒ 3b≥3a≥b^2 +b+1⇒(b−1)^2 ≤0⇒b=1⇒1≥a false ⇒b<a

Commented bymathdanisur last updated on 27/Jul/21

Thank you Ser