Question Number 148324 by Odhiambojr last updated on 27/Jul/21

x^2 −y^2 =3, find dy/dx

Answered by liberty last updated on 27/Jul/21

2x−2yy′=0 ⇒y′=(x/y)=(x/(± (√(x^2 −3))))

Answered by mathmax by abdo last updated on 27/Jul/21

x^2 −y^(2 ) =3 ⇒x^2 +3=y^2 ⇒y=+^− (√(x^2 +3)) ⇒ (dy/dx)=+^− ((2x)/(2(√(x^2 +3))))=+^− (x/( (√(x^2 +3))))