Question Number 148494 by liberty last updated on 28/Jul/21

(((3+2(√2))^(2008) )/((7+5(√2))^(1338) )) + (3−2(√2)) = log _2 (x) x=?

Answered by EDWIN88 last updated on 28/Jul/21

log _2 (x)=(((3+2(√2))^(2008) )/((7+5(√2))^(1338) )) +(3−2(√2)) log _2 (x)=(((1+(√2))^(2×2008) )/((3+2(√2))^(1338) (1+(√2))^(1338) ))+(3−2(√2)) log _2 (x)=(((1+(√2))^(4016) )/((1+(√2))^(4014) )) +(3−2(√2)) log _2 (x)=(1+(√2))^2 +3−2(√2) log _2 (x)=3+2(√2)+3−2(√2) =6 ⇒x = 2^6 = 64 [ love Jew ]