Question Number 148754 by mathdanisur last updated on 30/Jul/21

Commented byliberty last updated on 31/Jul/21

ans: 850

Answered by liberty last updated on 31/Jul/21

((sin ^6 36°)/(cos ^6 36°)) + ((sin ^6 72°)/(cos ^6 72°)) = (((1/2^6 )(2cos 72°sin 36°)^6 +(1/2^6 )(2sin 72°cos 36°)^2 )/((1/2^6 )(2cos 72°cos 36°)^6 )) =(((sin 108°−sin 36°)^6 +(sin 108°+sin 36°)^6 )/((sin 18°(1−2sin 18°))^6 )) =((cos ^6 18°(1−2sin 18°)^6 +cos ^6 18°(1+2sin 18°)^6 )/(sin ^6 18°(1−2sin 18°)^6 )) you can finish it

Commented byliberty last updated on 31/Jul/21

cos 18°=((√(2(√5)+10))/4) sin 18°=(((√5)−1)/4)

Commented bymathdanisur last updated on 31/Jul/21

Thank you Ser