Question Number 148914 by naka3546 last updated on 01/Aug/21

Solve the equation 2^x + x = 11 with Omega Function .

Commented bynaka3546 last updated on 01/Aug/21

thank you, sir.

Commented bymr W last updated on 01/Aug/21

2^(11) =(11−x)2^(11−x) 2^(11) ln 2=(11−x)ln 2e^((11−x)ln 2) (11−x)ln 2=W(2^(11) ln 2) x=11−((W(2^(11) ln 2))/(ln 2))=3