Question Number 149043 by Tawa11 last updated on 02/Aug/21

Commented byEDWIN88 last updated on 02/Aug/21

x=2

Commented byTawa11 last updated on 02/Aug/21

Workings sir.

Commented byTawa11 last updated on 02/Aug/21

Solve for x

Answered by EDWIN88 last updated on 02/Aug/21

2(√x) (u−v)=4(√(3 )) where { ((u=(√x) +(√(x+(√3))))),((v=(√x)−(√(x−(√3))))) :} ⇔2(√x) ((√(x+(√3))) +(√(x−(√3))) )=4(√3) ⇔(√(x^2 +x(√3))) +(√(x^2 −x(√3))) = 2(√3) ⇒2x^2 +2(√(x^4 −3x^2 )) = 12 ⇒(√(x^4 −3x^2 )) =6−x^2 (√(u^2 −3u)) = 6−u ; u=x^2 u^2 −3u=36−12u+u^2 ⇒9u=36⇒u=4 then x = 2 , since x=−2 rejected

Commented bybramlexs22 last updated on 02/Aug/21

nice

Commented byTawa11 last updated on 02/Aug/21

Thank you sir. God bless you

Commented byTawa11 last updated on 22/Aug/21

Sir. I could not get the first part since. That is: 2(√x) (u − v) = 4(√3) But I understand other steps very well.