Question Number 149112 by bramlexs22 last updated on 03/Aug/21

ϕ = ∫ tan (x+(π/3))tan 3x tan (2x−(π/3)) dx =?

Commented bysom(math1967) last updated on 03/Aug/21

tan3x=tan(x+(𝛑/3) +2x−(𝛑/3)) tan3x=((tan(x+(𝛑/3))+tan(2x−(𝛑/3)))/(1−tan(x+(𝛑/3))tan(2x+((2𝛑)/3)))) ∴tan3xtan(x+(𝛑/3))tan(2x−(𝛑/3)) =tan3x−tan(x+(𝛑/3))−tan(2x−(𝛑/3))

Commented bybramlexs22 last updated on 03/Aug/21

yes thanks