Question Number 149121 by mathdanisur last updated on 03/Aug/21

((2∙(cos85° + isin85°))/( (√2)∙(cos40° + isin40°))) = ?

Answered by bramlexs22 last updated on 03/Aug/21

(√2) e^(i(85°−40°) )=(√2) e^(i45°) =(√2)(((√2)/2)+((√2)/2)i) =1+i

Commented bymathdanisur last updated on 03/Aug/21

Ser, Thank You

Answered by Ar Brandon last updated on 03/Aug/21

=(√2)∙(e^(i85°) /e^(i40°) )=(√2)e^(i85°−i40°) =(√2)e^(i45°) =(√2)(cos45°+isin45°)=1+i

Commented bymathdanisur last updated on 03/Aug/21

Ser, Thank You