Question Number 149140 by mathdanisur last updated on 03/Aug/21

{ ((∣x∣ + y - 1 = 0)),((x - y - 1 = 0)) :} ⇒ 2x - 3y = ?

Commented byliberty last updated on 03/Aug/21

y= x−1 ⇒∣x∣+x−2=0 case(1) x<0 ⇒−x+x−2=0 ,no solution case(2)x>0⇒x+x−2=0 { ((x=1)),((y=0)) :} ⇒2x−3y=2

Commented bymathdanisur last updated on 03/Aug/21

Thank You Ser