Question Number 149188 by mathdanisur last updated on 03/Aug/21

f(x) = ax^(99) + bx^(77) + cx^(55) + 975 f(−975) = 1000 find f(975) = ?

Answered by mr W last updated on 03/Aug/21

g(x)=f(x)−975=ax^(99) +bx^(77) +cx^(55) g(−x)=−g(x) ⇒odd function g(−975)=−g(975) f(−975)−975=−(f(975)−975) f(−975)=2×975−f(975) f(−975)=2×975−1000=950

Commented bymathdanisur last updated on 03/Aug/21

Ser, Thank You

Answered by liberty last updated on 03/Aug/21

⇒1000=−a(975)^(99) −b(975)^(77) −c(975)^(55) +975 ⇒−25=a(975)^(99) +b(975)^(77) +c(975)^(55) f(975)=a(975)^(99) +b(975)^(77) +c(975)^(55) +975 = −25+975=950

Commented bymathdanisur last updated on 03/Aug/21

Ser, Thank You