Question Number 149292 by mathdanisur last updated on 04/Aug/21

if sin2𝛂 = - (1/3) find 3tg^2 (((3𝛑)/4) - 𝛂) = ?

Answered by Ar Brandon last updated on 04/Aug/21

sin2α=−(1/3) Θ=3tan^2 (((3π)/4)−α) =3(((tanα+1)/(tanα−1)))^2 =3(((sinα+cosα)/(sinα−cosα)))^2 =3((1+sin2α)/(1−sin2α))=3((2/3)×(3/4))=(3/2)

Commented bymathdanisur last updated on 04/Aug/21

Thank You Ser