Question Number 149309 by ArielVyny last updated on 04/Aug/21

if t=tanx what is the value of sinx and cosx ?

Answered by nimnim last updated on 04/Aug/21

sinx=(t/( (√(1+t^2 )))), cosx=(1/( (√(1+t^2 ))))

Answered by puissant last updated on 04/Aug/21

sin(x)=((∣t∣)/( (√(1+t^2 )))) ; cos(x)=(1/( (√(1+t^2 ))))..

Answered by mathmax by abdo last updated on 04/Aug/21

cos^2 x =(1/(1+tan^2 x))=(1/(1+t^2 )) ⇒cos(x)=+^− (1/( (√(1+t^2 )))) sin^2 x=1−cos^2 x =1−(1/(1+t^2 ))=(t^2 /(1+t^2 )) ⇒sinx =((∣t∣)/( (√(1+t^2 ))))