Question Number 149329 by mnjuly1970 last updated on 04/Aug/21

Commented byKamel last updated on 04/Aug/21

I think I^(100) +k≡0[14]

Answered by Kamel last updated on 04/Aug/21

∫_0 ^(π/2) ((e^(−tan(x)) sin^2 (x))/(cos^6 (x)))dx=^(t=tan(x)) ∫_0 ^(+∞) (t^2 +t^4 )e^(−t) dt=2+4!=26  26^(100) +k≡0[14]  26≡−2[14]⇒26^(100) ≡2^(100) [14]  2^4 ≡2[14]⇒2^(100) ≡2^(25) [14]⇒2^(100) ≡2^(10) [14]⇒2^(100) ≡2[14]  ∴ k≡−26^(100) [14]⇒k≡−2[14]⇒k≡12[14]  ∴ k=14n+12⇒k_(min) =12, k>0.

Commented bymnjuly1970 last updated on 05/Aug/21

         tashakor  mr kamel....