Question Number 149410 by mathdanisur last updated on 05/Aug/21

((log_2 2^(20) + log_2 20 ∙ log_2 5 - 2 log_2 2^5 )/(log_2 20 + 2 log_2 5)) = ?

Answered by Rasheed.Sindhi last updated on 05/Aug/21

((log_2 2^(20) + log_2 20 ∙ log_2 5 - 2 log_2 2^5 )/(log_2 20 + 2 log_2 5)) =((20 + log_2 20 ∙ log_2 5 - 2(5))/(log_2 20 + 2 log_2 5)) =((10 + log_2 (2^2 .5)∙ log_2 5 )/(log_2 (2^2 .5) + 2 log_2 5)) =((10 +(log_2 2^2 +log_2 5)∙ log_2 5 )/(log_2 2^2 +log_2 5 + 2 log_2 5)) =((10 +(2+log_2 5)∙ log_2 5 )/(2+ 3 log_2 5)) =((10 +2log_2 5+log_2 5∙ log_2 5 )/(2+ 3 log_2 5)) =((10 +2log_2 5+(log_2 5)^2 )/(2+ 3 log_2 5)) =((10 +2(2.3219)+(2.3219)^2 )/(2+ 3(2.3219)))≈2.2346

Commented bymathdanisur last updated on 05/Aug/21

Thank You Ser