Question Number 149437 by SLVR last updated on 05/Aug/21

Commented bySLVR last updated on 05/Aug/21

kindly solution please

Answered by Olaf_Thorendsen last updated on 05/Aug/21

• 1−digit numbers : 9 between 1 and 9 ⇒ 9 digits • 2−digits numbers : 90 between 10 and 99 ⇒ 180 digits • 3−digits numbers : 900 between 100 and 999 ⇒ 2700 digits 2021 = 9+180+1832 2021 = 9+180+(3×610+2) The 2021^(th) digit is the second digit of 611^(th) 3−digits number. The 611^(th) 3−digits number is 710. ⇒ Result is 1.

Commented bySLVR last updated on 05/Aug/21

yeah...GreatProf. olaf....nice