Question Number 149440 by nadovic last updated on 05/Aug/21

Answered by Olaf_Thorendsen last updated on 07/Aug/21

(a) A_1 = ♮persons from only one of the three groupsε. That means 3 volleyball players or 3 hockey players. P(A_1 ) = (C_3 ^3 /C_3 ^9 )+(C_3 ^4 /C_3 ^9 ) = (5/(84)) ≈ 5,95%. (b) A_2 = ♮two persons from one group and one person from another groupε. That means −1 football player and 2 volleyball players or −2 football players and 1 volleyball player or −1 football player and 2 hockey players or −2 football players and 1 hockey player or −1 volleyball player and 1 hockey players or −2 volleyball players and 1 hockey player. P(A_2 ) = ((C_1 ^2 C_2 ^3 )/C_3 ^9 )+((C_2 ^2 C_1 ^3 )/C_3 ^9 )+ ((C_1 ^2 C_2 ^4 )/C_3 ^9 )+ ((C_2 ^2 C_1 ^4 )/C_3 ^9 ) + ((C_1 ^3 C_2 ^4 )/C_3 ^9 )+((C_2 ^3 C_1 ^4 )/C_3 ^9 ) P(A_2 ) = (6/(84))+(3/(84))+ ((12)/(84))+ (4/(84))+((18)/(84))+((12)/(84)) P(A_2 ) = ((55)/(84)) ≈ 65,48%.

Commented bynadovic last updated on 07/Aug/21

Thank you Sir