Question Number 149458 by mathdanisur last updated on 05/Aug/21

Commented byEDWIN88 last updated on 06/Aug/21

n(S)=C_2 ^7 =((7×6)/(2×1))=21 n(A)= 18 A={(1,2),(1,4),(1,6),(2,3),(2,4), (2,5),(2,6),(3,4),(3,6),(4,5),(4,6), (5,6),(0,1),(0,2),(0,3),(0,4),(0,5) ,(0,6)} then P(A)=((18)/(21)) =(6/7)

Commented byEDWIN88 last updated on 06/Aug/21

X_(even) = {0,2,4,6} X_(odd) ={1,3,5} → { ((even×even=even)),((even×odd=even)) :} P(A_(product even) )=((C_2 ^4 +C_1 ^4 ×C_1 ^3 )/C_2 ^7 ) = ((6+4×3)/(21))=((18)/(21))=(6/7)

Commented bymathdanisur last updated on 06/Aug/21

Thanlyou Ser

Answered by mr W last updated on 05/Aug/21

p=1−((6+C_2 ^3 )/C_2 ^7 )=1−(9/(21))=(4/7)

Commented bymathdanisur last updated on 05/Aug/21

Thank you Ser, but answer: (2/(15))

Commented bymr W last updated on 05/Aug/21

i can get the same result in an other way: p=((3×3+3)/(21))=(4/7) other people should check if i′m wrong or you are wrong.

Commented bymathdanisur last updated on 05/Aug/21

Thankyou Ser

Commented byEDWIN88 last updated on 06/Aug/21

mr W your answer not correct. please check

Commented bymr W last updated on 06/Aug/21

i excluded zero. p=1−((6+C_2 ^3 )/C_2 ^7 )=1−(9/(21))=(4/7) if zero is included, then p=1−(C_2 ^3 /C_2 ^7 )=1−(3/(21))=(6/7)

Commented bymathdanisur last updated on 06/Aug/21

Thankyou Ser